• VOLUME AND SURFACE AREA >> SOLVED EXAMPLES

• VOLUME AND SURFACE AREA >> IMPORTANT FACTS AND FORMULA

Tags : Aptitude Volume and Surface Area, Aptitude Volume and Surface Area Questions Answers, Aptitude Volume and Surface Area Problems, Aptitude Test Questions and Answers on Volume and Surface Area,  Aptitude Questions and Answers for Volume and Surface Area, Volume and Surface Area Questions and Answers, Mba Model Questions and Answers, Quantitative Aptitude Questions for Bank Exams, Bank Po Quantitative Aptitude Questions, English Aptitude Questions and Answers, Interview Aptitude Questions and Answers, Computer Aptitude Questions with Answers for Bank Exams, Banking Aptitude Questions and Answers

1.	How many minutes does John take to cover a distance of 400 m, if he runs at a speed of 20 km/hr?
	Sol. John’s speed = 20 km/hr = [20*5/18] m/sec = 50/9 m/sec.
2.	While covering a distance of 24 km, a man noticed that after walking for 1 hour and 40 minute, the distance covered by him was 5/7 of the remaining distance. What was his speed in metres per second?
	Sol. Let the speed be x km/hr. Then, distance covered in 1 hr: 40 min. i.e., 1 2/3 hrs = 5x/3 km. Remaining distance = [24-5x/3] km. ∴ 5x/3 = 5/7[24-5x/3] ⇔ 5x/3 = 5/7[72-5x/3] ⇔ 7x = 72-5x ⇔ 12x = 72 ⇔ x = 6 Hence, speed = 6 km/hr = [6*5/18] m/sec = 5/3m/sec = 1 2/3 m/sec
3.	If a man walks at athe rate of 5 kmph, he misses a train by 7 minutes. However, if he walks at the rate of 6 kmph, he reaches the station 5 minutes before the arrival of the train. Find the distance covered by him to reach the station.
	Sol. Let the required distance be x km. Difference in the times taken at two speeds = 12 min = 1/5 hr. ∴ x/5 - x/6 = 1/5 ⇔ 6x - 5x = 6 ⇔ x = 6. Hence, the required distance is 6 km.

1.	Speed = [Distance/Time], Time=[Distance/Speed], Distance = (Speed*Time)
2.	x km/hr = [x*5/18] m/sec.
3.	If the ratio of the speeds of A and B is a:b, then the ratio of the times taken by them to cover the same distance is 1/a : 1/b or b:a.
4.	x m/sec = [x*18/5] km/hr.
5.	Suppose a man covers a certain distance at x km/hr and an equal distance at y km/hr. then, the average speed during the whole journey is [2xy/x+y] km/hr.